Question

A motorbike reaches a speed of 20 m/s over 60m, whilst

accelerating at 3m/s?, determine the bike's initial speed.

Answer 1

Initial speed = 2√10 m/s

Further explanation

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

An equation of uniformly accelerated motion

V = vo + at

Vt² = vo² + 2a (x-xo)

x = distance on t

vo / vi = initial speed

vt / vf = speed on t / final speed

a = acceleration

vf=20 m/s

d = 60 m

a = 3 m/s²

`\tt vf^2=vi^2+2.ad\\\\20^2=vi^2+2* 3* 60\\\\400=vi^2+360\\\\40=vi^2\\\\vi=√(40)=2√(10)~m/s`