Question

The distance from Mason's house to Kevin's house is about 5 × 105 inches. The distance from Mason's house to Chloe's house is about 8 × 107 inches. The distance from Mason's house to Chloe's house is how many times as great as the distance from Mason's to Kevin's house?

Answer 1

Distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.

Explanation:

Let the distance from Mason's house to Chloe's house is x times as great as the distance from Mason's to Kevin's house.

Distance from Mason's house to Kevin's house=
`5 * 10^5` inches.

Distance from Mason's house to Chloe's house =
`8 * 10^7` inches

ATQ

`8 * 10^7= x * 5 * 10^5 \\(8 * 10^7)/(5 * 10^5)=x\\160=x`

So, distance from Mason's house to Chloe's house is 160 times as great as the distance from Mason's to Kevin's house.

Hence distance from Mason's house to Chloe's house is 160 as great as the distance from Mason's to Kevin's house.