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The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated by a normal distribution with a mean value of 110 sec and a standard deviation of 15 sec. The fastest 10% are to be given advanced training. What task times qualify individuals for such training? (Round the answer to one decimal place.) seconds or less

1 Answer

6 votes

Answer:

The task times is
x =90.77 \ s

Explanation:

From the question we are told that

The mean is
\mu  =  110 \ sec

The standard deviation is
\sigma =  15 \  sec

Generally the task times that qualify individuals for such training is mathematically represented as


P(X &nbsp;< &nbsp;x) = &nbsp;0.10

=>
P(X &nbsp;< &nbsp;x) = P( (X - \mu)/(\sigma ) &nbsp;< &nbsp;(x - 110)/(15) ) &nbsp;= 0.10

Generally
(X - \mu)/(\sigma ) &nbsp; = Z (The &nbsp;\ standardized \ &nbsp;value &nbsp;\ &nbsp;of &nbsp;X )

=>
P(X &nbsp;< &nbsp;x) = P( Z < &nbsp;(x - 110)/(15) ) &nbsp;= 0.10

Generally the z -score of 0.10 from the z-table is


z -score = &nbsp;-1.282

So


(x - 110)/(15) &nbsp; = &nbsp;-1.282

=>
x =90.77 \ s

User Ocramz
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