Answer:
There are 7 ten-dollar bills and 16 five-dollar bills.
Explanation:
Let's call:
T: Number of ten-dollar bills
F: Number of five-dollar bills
The amount of money withdrawn from the ATM is $150:
10T+5F=150
Dividing by 5:
![2T+F=30\qquad\qquad [1]](https://img.qammunity.org/2021/formulas/mathematics/college/ft6vfxacu1cvvuygn5usmgiwon2vza44ea.png)
We also know there are two more than twice as many five-dollar bills as there are ten-dollar bills:
![F=2+2T\qquad\qquad [2]](https://img.qammunity.org/2021/formulas/mathematics/college/3gvvvgx3m7emv980fohc5a89aennml7wrt.png)
Substituting [2] into [1]:
2T+2T+2=30
Rearranging:
2T+2T=30-2
Simplifying:
4T=28
Solving:
T=28/4=7
From [2]:
F=2+2*7=2+14=16
There are 7 ten-dollar bills and 16 five-dollar bills.