118k views
3 votes
The kind of bond present in CUSO4.5H20​

User Indra
by
4.9k points

1 Answer

2 votes

Answer:

Both ionic bonds and covalent bonds (coordinate and non-coordinate) are present in crystalline
\rm CuSO_4\cdot 5\, H_2O.

Step-by-step explanation:


\rm CuSO_4\cdot 5\, H_2O can be formed by adding water to the anhydrous salt
\rm CuSO_4.


\rm CuSO_4 itself is an ionic compound consisting of
\rm Cu^(2+) ions and
\rm {SO_4}^(2-) ions. Ionic bonds are present between these ions. However, within each sulfate
\rm {SO_4}^(2-) ion, covalent bonds connect the central sulfur atom to each of the oxygen atoms.

Water molecules
\rm H_2O are highly polar. Partial negative charges surround the oxygen atom in each water molecule.

When water is added to anhydrous
\rm CuSO_4, the negatively-charged portion of these
\rm H_2O\! molecules would be attracted to the positively-charged
\rm Cu^(2+) ions in
\rm CuSO_4\!.

Lone pairs on oxygen atoms in
\rm H_2O\!\! would form coordinate covalent bonds with
\rm Cu^(2+)\! ions. (These bonds are considered "coordinate" because both electrons in each of these bonds come from the oxygen atom, not the
\rm Cu^(2+) ion.) That would produce coordination complexes with one
\rm Cu^(2+)\!\! ion and five
\rm H_2O\!\!\! "ligands" each.

Because the
\rm H_2O ligands carry no electric charge, each of these complexes would also carry a charge of
(+2) (same as the charge on one
\rm Cu^(2+)\!\! ion.) Ionic bonds would be present between the positively-charged coordination complexes and the negatively-charged
\rm {SO_4}^(2-) ions.

Summary:

  • Covalent bonds are present within
    \rm {SO_4}^(2-) ions and
    \rm H_2O ligands.
  • Coordinate covalent bonds are present between
    \rm H_2O ligands and
    \rm Cu^(2+) ions.
  • Ionic bonds are present between
    \rm {[Cu\, (H_2O)_5]}^(2+) coordination complexes and sulfate ions
    \rm {SO_4}^(2-).
User Princesa
by
4.9k points