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Omg I can't work this one out, help!!

You can also check whether I did wrong on the other ones but help me on the last question​

Omg I can't work this one out, help!! You can also check whether I did wrong on the-example-1
User Maiasaura
by
3.8k points

1 Answer

10 votes

Answer:

a) 26 tickets

b) £5

c) chips, pastie and a soft drink

Explanation:

Given:

  • Price of one ticket = £7.50
  • Total available to spend = £200

Part (a)

Greatest number of tickets = total available to spend ÷ cost of one ticket

= 200 ÷ 7.5

= 26.66666...

= 26 tickets

(We can't round up, as 27 tickets would cost £202.50)

Part (b)

Money left = Total available spend - cost of 26 tickets

= 200 - (26 × 7.50)

= 200 - 195

= £5

Part (c)

Cost of 3 items = £10 - change

= £10 - £4.70

= £5.30

One of the items can't be a burger, as £5.30 - £3.50 = £1.80
and £1.80 is not enough to buy 2 items.

If he buys chips, he has: £5.30 - £2.40 = £2.90 left to spend on the other 2 items.

Pastie + Soft Drink = £1.60 + £1.30 = £2.90

So he can buy: chips, pastie and a soft drink

User Wiktor Bednarz
by
3.5k points