Question

Which of the following quadratic equations has no real solutions?

A 3x2 + 12x + 12 = 0
B 3x2 – 3x - 18 = 0
3x2 + 2x + 1 = 0
D
3x2 – 3 = 0

Answer 1

C. 3x^2 + 2x + 1

Explanation:

A. 12^2 - (4*3*12) = 0 (there's one solution.)

B. (-3)^2 - (4*3*-18) = 255 (there're 2 real solutions.)

D. 3^2 - (4*0*-3) = 9 (there're 2 real solutions.)

C. 2^2 - (4*3*1) = -18 ✅✅

if b^2 - 4ac = negative then we can say that there isn't any real solution for the equation.