Question

Which value of x is a possible solution to (2x−10)(3x+12)=0?

A: r = -36
B: r = -20
C: r = -5
D: r = -4

Answer 1

D: r = -4

Step-by-step explanation:

`\rightarrow \sf (2x-10)(3x+12)=0`

set to zero

`\rightarrow \sf 2x-10=0, \:3x+12=0`

change sides

`\rightarrow \sf 2x=10, \:3x=-12`

simplify

`\sf \rightarrow x=5,\:x=-4`

Answer 2

D: x = -4

Step-by-step explanation:

Given equation:

(2x - 10)(3x + 12) = 0

Therefore:

⇒ 2x - 10 = 0

⇒ 2x = 10

⇒ x = 5

And:

⇒ 3x + 12 = 0

⇒ 3x = -12

⇒ x = -4

So the possible solutions of the equation are x = 5 or x = -4