Question

Need help with this right now, please.

Answer 1

The answer above you is right

Answer 2

see below

Explanation:

the circumference of a circle is

`2\pi r`

in our problem

r=11

`C=2\pi (11)\\\\=22\pi`

rounded to the nearest tenth

`C\approx69.1`

the area of a circle is

`\pi r^2`

so the area is

`A=\pi(11)^2\\\\=121\pi`

rounded to nearest tenth

`A\approx 380.1`