Question

3. A student took a calibrated 200.0 gram mass, weighed it on a laboratory balance, and

found it read 196.5 9. What was the student's percent error?

Answer 1

The answer is 1.71 %

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual mass = 200 g

error = 200 - 196.59 = 3.41

We have

`p(\%) = (3.41)/(200) * 100 \\ = 1.705`

We have the final answer as

1.71 %

Hope this helps you