Question

If 298 mL of 0.575 M CuCl2 is diluted into 750 mL, what is the concentration of new solution?

Answer 1

The answer is 0.228 M

Step-by-step explanation:

To find the concentration of new solution we use the formula

`C_1V_1 = C_2V_2`

where

C1 is the concentration of the stock solution

V1 is the volume is the volume of the stock solution

C_2 is the concentration of the diluted solution

V2 is the volume of the diluted solution

Since we are finding the the concentration of new solution

`C_2 = (C_1V_1)/(V_2) \\`

From the question

C1 = 0.575 M

V1 = 298 mL

V2 = 750 mL

We have

`C_2 = (0.575 * 298)/(750) \\ = 0.228466666...`

We have the final answer as

0.228 M

Hope this helps you