Answer: 0.86 "L" 1 "mol" of "Zn" has mass of 65.39 "g". The amount of "Zn" is frac{2.5 "g"}{65.39 "g/mol"} = 0.038 "mol". The amount of "H"_2 produced is the same as the amount of "Zn" consumed (0.038 "mol").
Step-by-step explanation:
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