Question

Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.​

Answer 1

35 and 36

Explanation:

To solve this problem, we must interpret it line by line;

• We are dealing with consecutive integers; these are integers with a difference of 1 between them.

let the first number = x

second number = x + 1

• one - fifth of first;

`(1)/(5)`x

• one - ninth of the second;

`(1)/(9)`(x + 1)

for the "less" ;

`(1)/(5)`x -
`(1)/(9)`(x + 1) = 3

Multiply through by 45

45(
`(1)/(5)`x) - (45)
`(1)/(9)`(x + 1) = 3 x 45

9x - 5(x + 1) = 135

9x - 5x -5 = 135

4x = 135 + 5

4x = 140

x = 35

Now, x+1 = 35 + 1 = 36

The consecutive integers are 35 and 36