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A ball is hit into air at time t=0 seconds.its height above the ground is given by the equation h=25t-9.8t².what is the value of t when the ball lands on the ground?

User Gcas
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1 Answer

4 votes

Answer:

The ball lands on the ground at t=2.55 seconds

Explanation:

Quadratic Equation

The following function models the height above the ground of a ball hit into the air at time t seconds:


h=25t-9.8t^2

We need to find the value of t when the ball hits the ground.

At ground level, h is zero, thus:


25t-9.8t^2=0

This is an incomplete quadratic equation that can be easily solved by factoring:


t(25-9.8t)=0

There are two solutions:

t=0

t=25/9.8=2.55 s

The first solution corresponds to the moment when the ball is hit, and the second is when it returns to the ground, thus:

The ball lands on the ground at t=2.55 seconds

User Gogstad
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