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Triangle ABC has vertices A (1,1) B (7,1) C (4,9) (A)Find the perimeter of triangle ABC. (B) Find the area of triangle ABC​

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9514 1404 393

Answer:

  • perimeter = 6+2√73 ≈ 23.09 units
  • area = 24 units²

Explanation:

It can help to draw a figure.

The altitude of this isosceles triangle is 8 units, and it splits the base into equal lengths of 3 units. Using the Pythagorean theorem, we find the length of a side to be ...

BC = AC = √(3² +8²) = √73

The perimeter is the sum of the lengths of those two sides and the base:

P = 2(√73) +6 ≈ 23.088 . . . units

The area is given by the formula ...

A = 1/2bh

A = (1/2)(6 units)(8 untis) = 24 units²

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The perimeter is 6+2√73 ≈ 23.09 units.

The area is 24 units².

Triangle ABC has vertices A (1,1) B (7,1) C (4,9) (A)Find the perimeter of triangle-example-1
User Muhammad Taqi
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