Question

How do you Subtract 9x^2 + 22x - 46 from 12x^2 - 8x + 12.

Answer 1

Subtract the
`x^2` terms from each other, then the
`x` terms, then the ones without any
`x` whatsoever.

`(12x^2 - 8x + 12) - (9x^2 +22x-46)`

First, we'll subtract
`9x^2` from
`12x^2`

`12x^2-9x^2- = 3x^2`

Result:
`3x^2`

Next, we'll subtract
`22x` from
`-8x`

`-8x - 22x = -30x`

Result:
`-30x`

Finally, we'll subtract
`-46` from
`12`

`12-(-46) = 12+46 = 58`

Result:
`58`

Now, we can add these 3 results together.

First, we had
`3x^2`, then
`-30x`, and finally
`58`.

Thus, our subtraction of

`(12x^2 - 8x + 12) - (9x^2 +22x-46)`

equals

`3x^2-30x+58`