P = 11.133 atm (purple)
T = -236.733 °C(yellow)
n = 0.174 mol(red)
Further explanation
Some of the laws regarding gas, can apply to ideal gas (volume expansion does not occur when the gas is heated),:
- Boyle's law at constant T, P = 1 / V
- Charles's law, at constant P, V = T
- Avogadro's law, at constant P and T, V = n
So that the three laws can be combined into a single gas equation, the ideal gas equation
In general, the gas equation can be written
![\large {\boxed {\bold {PV = nRT}}}](https://img.qammunity.org/2021/formulas/chemistry/high-school/r7pk0vxu2d3qfmsxv5ilqrbl3jcu8p3c50.png)
where
P = pressure, atm
V = volume, liter
n = number of moles
R = gas constant = 0.08206 L.atm / mol K
T = temperature, Kelvin
To choose the formula used, we refer to the data provided
Because the data provided are temperature, pressure, volume and moles, than we use the formula PV = nRT
T= 10 +273.15 = 373.15 K
V=5.5 L
n=2 mol
![\tt P=(nRT)/(V)\\\\P=(2* 0.08205* 373.15)/(5.5)\\\\P=11.133~atm](https://img.qammunity.org/2021/formulas/chemistry/high-school/gysz1e4jjrvy2o05mledpc7yfjjmuhin14.png)
V=8.3 L
P=1.8 atm
n=5 mol
![\tt T=(PV)/(nR)\\\\T=(1.8* 8.3)/(5* 0.08205)\\\\T=36.42~K=-236.733^oC](https://img.qammunity.org/2021/formulas/chemistry/high-school/y2k94v08js21zdjftndcp2klsnop8kxnjh.png)
T = 12 + 273.15 = 285.15 K
V=3.4 L
P=1.2 atm
![\tt n=(PV)/(RT)\\\\n=(1.2* 3.4)/(0.08205* 285.15)\\\\n=0.174~mol](https://img.qammunity.org/2021/formulas/chemistry/high-school/6zg37x8p8yfgmklricsm9hbvdv5fremp53.png)