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Let f(x)= x^2 -5x+4 and g(x)=2^x-3
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Let f(x)= x^2 -5x+4 and g(x)=2^x-3

Let f(x)= x^2 -5x+4 and g(x)=2^x-3-example-1
User Rajenpandit
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Answer:

Plug g(x) into all the x values in your f(x) and the answer is 3 because it makes the denominator 1-1 which makes it 0 and is thus discontinuous

Explanation:

User Alex Kucherenko
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