Question

10. Predict the mass of nitrogen dioxide produced if 2.30 L of ammonia are allowed to react

with excess oxygen gas at STP?​

Answer 1

Mass of nitrogen dioxide produced = 4.6 g

Step-by-step explanation:

Given data:

Volume of ammonia = 2.30 L

Mass of nitrogen dioxide produced = ?

Solution:

Chemical equation:

4NH₃ + 7O₂ → 4NO₂ + 6H₂O

Number of moles of ammonia at STP:

PV = nRT

n = PV/RT

n = 1 atm × 2.30 L / 0.0821 atm.L/K.mol × 273 K

n = 2.30 atm .L / 22.414 atm.L/mol

n = 0.1 mol

Now we will compare the moles of ammonia with nitrogen dioxide from balance chemical equation.

NH₃ : NO₂

4 : 4

0.1 : 0.1

Mass of NO₂:

Mass = number of moles × molar mass

Mass = 0.1 mol × 46 g/mol

Mass = 4.6 g