Answer:
Graph E is correct.
Solving Stepwise:
Given Expression: |x| < 3
Apply the absolute rule when |u| < a, then -a < u < a
Values are between -3 and 3
Explanation:
The circle should be closed when the inequality is "≤" and "≥"
The circle should be opened when the inequality is "<" and ">"
Here we have "<", so the circle should be kept open.