Question

Two velocity vectors, one is twice of the other, and separated by 90 Degree angle. If their resultant is calculated 90 m/s, what the magnitude of bigger vector?

Answer 1

Vy = 80.5 [m/s]

Step-by-step explanation:

In order to solve this problem we must use the Pythagorean theorem.

V = 90 [m/s]

The components are Vx and Vy:

Therefore:

`v=\sqrt{v_(x)^(2) + v_(y)^(2) }`

where:

Vy = 2*Vx ; because one is twice of the other.

`90 = \sqrt{v_(x)^(2) +(2*v_(x))^(2) }\\ 90 =\sqrt{v_(x)^(2)+4*v_(x)^(2)} \\90 =\sqrt{5v_(x)^(2)} \\90=2.23*v_(x) \\v_(x)=40.25[m/s]`

and the bigger vector is:

Vy = 40.25*2

Vy = 80.5 [m/s]