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In a certain semiconducting material the charge carriers each have a charge of 1.6 x 10-19

C. How many are entering the semiconductor per second when the current is 2.0 nA?

User DoubleE
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1 Answer

5 votes

Answer:

1124923453 electrons

Step-by-step explanation:

The formula for charge in coulomb ,C =Current in amperes, A * Time in seconds, s

Given in question ;

Charge = 1.6 * 10⁻¹⁹ C

Current = 2.0 nA = 2*e⁻⁹ A

Calculate time in seconds as

1.6 * 10⁻¹⁹ = 2*e⁻⁹ * t

1.6 * 10⁻¹⁹ /2*e⁻⁹ = t

6.48e⁻¹⁶ s = t

So using t=6.48e⁻¹⁶ s and current =2*e⁻⁹ A , the charge will be;

C = 2*e⁻⁹ * 6.48e⁻¹⁶ =1.799e⁻¹⁰ C

But 1 coulomb = 6.25 x 10¹⁸ electrons

so 1.799e⁻¹⁰ C = ?,,,,{ 6.25 x 10¹⁸} *{1.799e⁻¹⁰} = 1124923453.06 electrons

User Xiaq
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