Question

Find the domain and range of f(x)=x/x^2-9

Answer 1

`Dom(f)=(-\infty, -3 )\cup (-3, 3 )\cup (3,-\infty )`

`Ran(f)=\matyhbb{R}`

Explanation:

`f(x)=(x)/(x^2-9)`

Once the denominator can't be zero,
`x\\eq 3` and
`x\\eq -3`

`Dom(f)=(-\infty, -3 )\cup (-3, 3 )\cup (3,-\infty )`

The range from the graph is all Real numbers