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Find the distance between the two points in simplest radical form.

n.
(6, -9) and (1,3)
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Find the distance between the two points in simplest radical form. n. (6, -9) and-example-1

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\large\underline{\underline{\red{\sf \blue{\longmapsto} Step-by-step\: Explanation:-}}}

Given to points to us are :-

  • ( 6 , -9)
  • ( 1 , 3 )

Now , we can use Distance Formula , which is :-


\boxed{\purple{\tt Distance=√((x_2-x_1)^2+(y_2-y_1)^2)}}

Here ,

  • x1 = 6 .
  • x2 = 1.
  • y1 = (-9)
  • y2 = 3.

→ Substituting the respective values ,

⇒ Distance = √ [ ( 6 - 1)² + ( 3 +9)² ] .

⇒ Distance = √ 5² + 12²

⇒ Distance = √ 25 + 144

⇒ Distance = √ 169 .

⇒ Distance = 13 units .

Hence the distance between two points is 13u.

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