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Which is the completely factored form of 12x3 – 60x2 + 4x – 20?

User Dave Ceddia
by
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1 Answer

14 votes
14 votes

Answer:


4(x-5)(3{x}^(2)+1)

Explanation:

1) Find the Greatest Common Factor (GCF).

1 - What is the largest number that divides evenly into
12x^3,-60x^2,4x, and
-20 ?

It is
4.

2 - What is the highest degree of
x that divides evenly into
12x^3,-60x^2,4x, and
-20 ?

It is 1, since
x is not in every term.

3 - Multiplying the results above,

The GCF is 4.

2) Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)


4(\frac{12{x}^(3)}{4}+\frac{-60{x}^(2)}{4}+(4x)/(4)-(20)/(4))

3) Simplify each term in parentheses.


4(3{x}^(3)-15{x}^(2)+x-5)

4) Factor out common terms in the first two terms, then in the last two terms.


4(3{x}^(2)(x-5)+(x-5))

5) Factor out the common term
x-5.


4(x-5)(3{x}^(2)+1)

User DerekH
by
2.8k points