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Which equation shows the point-slope tor of the line that passes through (3, 2) and has a slope of 1/3

Y+ 2 = 1/3 (x + 3)
y -2 = 1/3 (x-3)
y+3 = 1/3 (x+3)
y - 3 = 1/3 (x - 2)

User Isagalaev
by
7.7k points

2 Answers

2 votes

Answer:

y - 2 =
(1)/(3) (x - 3)

Explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m =
(1)/(3) and (a, b) = (3, 2) , thus

y - 2 =
(1)/(3)(x - 3)

User Lyjackal
by
8.1k points
2 votes

Given : A line passes through a point ( 3 , -2 ) and the slope of the line is ⅓ .

To Find : The equation of that line .

Solution : Here we are provided with a point ( 3 , -2 ) and slope of the line which is ⅓ . So clearly here to represent the line we will use point - slope form , which is ;


\large\underline{\boxed{\red{\bf y - b = m ( x - a ) }}}

Where ,

  • a is x - coordinate.
  • b is y - coordinate .
  • m is the slope of the line .

Here ,

  • a = 3
  • b = -2
  • m = ⅓ .

Now , put the respective values ;


\boxed{\purple{\sf y - 2 = (1)/(3)(x-3)}}

User Eric White
by
8.6k points

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