Answer:


y-intercept = 40
Explanation:

Take two ordered pairs from the table:


Substitute them into the slope formula and solve for m:

Use the point-slope form of a linear equation with the found value of m and the point (0, 40):



Slope-intercept form of a linear equation:

(where m is the slope and b is the y-intercept).
Comparing with the calculated equation:
y-intercept = 40