Question

PLEASE HELP!!

There are 5.5 L of a gas present at -38.0 C. What is the temperature if the volume of the gas has changed to 1.30 L?

Answer 1

The answer is 55.54 K

Step-by-step explanation:

In order to find out the final temperature we use the formula for Charles's law which is

`(V_1)/(T_1) = (V_2)/(T_2) \\`

where

V1 is the initial volume

T1 is the initial temperature in Kelvin

V2 is the final volume

T2 is the final temperature in Kelvin

Since we are finding the final temperature

`T_2 = (V_2T_1)/(V_1) \\`

rom the question

V1 = 5.5 L

T1 = -38°C = -38 + 273 = 235 K

V2 = 1.30 L

We have

`T_2 = (1.30 * 235)/(5.5) = (305.5)/(5.5) \\ = 55.545454...`

We have the final answer as

55.54 K

Hope this helps you