Question

Fiind the value of x between 0 and 360
for question 5sin 2x=7cos2x​

Answer 1

x=pi*n/2+1/2arctan(7/5)

Explanation:

5sin(2x)=7cos(2x)

5tan(2x)=7/5

2x=pi*n+arctan(7/5)

x=pi*n/2+1/2arctan(7/5) for n e Z