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CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE. Determine m∠ABQ and determine m∠BCR.

CAN SOMEONE PLEASE HELP ME ASAP PLEASEE ANYBODY LITERALLY ANYONE OUT THERE PLEASE-example-1

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Answer:

ABQ = 139

BCR is the same as QBC since they are alternate interior angles

BCR = 41

Explanation:

CBQ and SCB are same side interior angles so they add to 180

2a-9 + 5a +14 = 180

Combine like terms

7a +5 = 180

Subtract 5 from each side

7a = 175

Divide by 7

7a/7 = 175/7

a = 25

ABQ is the same as SCB since they are corresponding angles so

ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139

BCR is the same as QBC since they are alternate interior angles

BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41

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