Question

What is the volume of 11.2 g of O2 at 7.78 atm and 415 K?

Answer 1

1.53 L

Step-by-step explanation:

Step 1: Given data

• Mass of oxygen (m): 11.2 g

• Pressure (P): 7.78 atm

• Temperature (T): 415 K

• Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

11.2 g × (1 mol/32.00 g) = 0.350 mol

Step 3: Calculate the volume of oxygen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm

V = 1.53 L