Calculate the Molarity of the following solutions. Please explain

asked Jan 14, 2023 191k views

5 votes

3.3k points

Please log in or register to add a comment.

8 votes

$\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}}$

0.12

Step-by-step explanation:

$\mathfrak {molarity = (no. \: of \: moles)/(volume \: of \: solution) }$

$\sf 1 \: mole \: of \: Al_2(SO_4)_3 = 342g \\ \\ \sf 31.1g \: of \: Al_2(SO_4)_3 = (31.1)/(342) = 0.09 \: moles \\ \\ \sf volume = 755ml = 0.755l$

$\sf \longmapsto molarity = (0.09)/(0.755) \\ \\ \\ \sf \longmapsto 0.12 \: mol \: {l}^( - 1)$

Almir Vuk answered Jan 20, 2023

3.7k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

3.4m questions

4.3m answers