Question

Pls solve question 4b. Verrry urgent . Ok tyy

Answer 1

`y = 3\left(x-(3)/(2)\right)^2+(41)/(4)`

Explanation:

Given equation:

`y = 3x^2 - 9x + 17`

Factor out 3 from the first 2 terms:

`y = 3(x^2 - 3x) + 17`

Divide the coefficient of x by 2 and square it: (-3 ÷ 2)² = 9/4

Add this inside the parentheses and subtract the distributed value of it outside the parentheses:

`y = 3\left(x^2 - 3x+(9)/(4)\right) + 17-(27)/(4)`

Factor the parentheses and combine the constants:

`y = 3\left(x-(3)/(2)\right)^2+(41)/(4)`