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How many times do you subtract 7 from 1999 and 5 from 1701 to get an equal number?

1 Answer

1 vote

Answer:

149 times.

Explanation:

Let n be the number we are looking for.

The we have to solve this equation:

1999 - 7n = 1701 - 5n

⇔ 1999 - 1701 = 7n - 5n

⇔ 298 = 2 n

⇔ n = 298/2

⇔ n = 149

Verification :

1 999 - 7×149 = 956

1 701 - 5×149 = 956

User TimPietrusky
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