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12 votes
B. Show that tan(45+ A) = 1+ tan A 1- tan A​

User SolidSnake
by
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2 Answers

11 votes

Answer:

See below ~

Explanation:

Solving :

Taking the LHS :

  • tan (45 + A)

Formula :

  • tan (x + y) = tan x + tan y / 1 - (tan x)(tan y)

Solving :

  • tan (45 + A) = tan 45° + tan A / 1 - (tan 45°)(tan A)
  • tan (45 + A) = 1 + tan A / 1 - tan A (because tan 45° = 1)
  • Equal to the RHS

∴ Hence, it is proved √

User Aydar Omurbekov
by
8.0k points
5 votes

LHS = tan(45° - A)


=(tan45-tanA)/(1+tan45tanA)


=(1-tanA)/(1+tanA) =RHS

User Kahiem
by
8.2k points

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