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Let f(x,y)=x²-3xy-y² Compute f(5,0) and f(5,-3).
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Let f(x,y)=x²-3xy-y² Compute f(5,0) and f(5,-3).

User Khrizenriquez
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1 Answer

2 votes

Answer:

f(5, 0) = 25

f(5, -3) = 61

Explanation:

f(x, y) = x² - 3xy - y²

⇒ f(5, 0) = (5)² - 3(5)(0) - (0)²

= 25 - 0 - 0

= 25

⇒ f(5, -3) = (5)² - 3(5)(-3) - (-3)²

= 25 - 15(-3) - 9

= 25 + 45 - 9

= 61

User Chetan J Rao
by
4.8k points
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