Answer:
The horizontal displacement is 20 m.
Step-by-step explanation:
Given that,
Velocity = 10 m/s
Height = 20 m
We need to calculate the time
Using equation of motion
![s=ut+(1)/(2)gt^2](https://img.qammunity.org/2021/formulas/physics/high-school/xzook2hxwg8pnpks7hgxxw2aujuk14vaic.png)
Put the value into the formula
![20=0+(1)/(2)*9.8* t^2](https://img.qammunity.org/2021/formulas/physics/college/zpg88vifvzrffguocerh1b3e9u5hin3rah.png)
![t^2=(20*2)/(9.8)](https://img.qammunity.org/2021/formulas/physics/college/cx0d7itibytwyzmuumqigryg0o9x9din9g.png)
![t=\sqrt{(20*2)/(9.8)}](https://img.qammunity.org/2021/formulas/physics/college/18sqg8eb3wm0j2b8ipuzd58mq5delq5u9p.png)
![t=2.0\ sec](https://img.qammunity.org/2021/formulas/physics/college/j373njulm8uwbmu3fti3gh6uxxpnocle4h.png)
We need to calculate the horizontal displacement
Using formula of horizontal displacement
![\Delta x=v_(x)* t](https://img.qammunity.org/2021/formulas/physics/college/7ztecllxorki8tqx9bl46b9nci0htqfvjp.png)
Put the value into the formula
![\Delta x=10*2.0](https://img.qammunity.org/2021/formulas/physics/college/ub7642b7hp2bq15rc2wbjm8vtvocy7vqui.png)
![\Delta x=20\ m](https://img.qammunity.org/2021/formulas/physics/college/k3jmf548vwrmj5lk561bbkxgxyg6pgws8q.png)
Hence, The horizontal displacement is 20 m.