Question

Plz help asap I’ll give you 100 points

Answer 1

`\textsf{Perimeter}= 8x^2+12y`

Explanation:

A rectangle has 2 pairs of parallel, congruent sides.

The perimeter of a two-dimensional shape is the distance all the way around the outside. Therefore, the perimeter of a rectangle is twice the sum of its length and width.

Given:

• width =
  `x + 4y`
• length =
  `4x^2-x+2y`

Therefore:

`\begin{aligned}\sf Perimeter & = 2(\sf width + length)\\& = 2 \left((x+4y)+(4x^2-x+2y)\right)\\& = 2(x+4y+4x^2-x+2y)\\& = 2x+8y+8x^2-2x+4y\\& = 8x^2+2x-2x+8y+4y\\& = 8x^2+12y\end{aligned}`

Answer 2

• P = 8x² + 12y units

Explanation:

Given sides of rectangle:

• x + 4y
• 4x² - x + 2y

Its perimeter is:

• P = 2(l + w)
• P = 2(x + 4y + 4x² - x + 2y)
• P = 2(4x² + 6y)
• P = 8x² + 12y