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Plz help asap I’ll give you 100 points

Plz help asap I’ll give you 100 points-example-1
User Danopz
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2 Answers

24 votes
24 votes

Answer:


\textsf{Perimeter}= 8x^2+12y

Explanation:

A rectangle has 2 pairs of parallel, congruent sides.

The perimeter of a two-dimensional shape is the distance all the way around the outside. Therefore, the perimeter of a rectangle is twice the sum of its length and width.

Given:

  • width =
    x + 4y
  • length =
    4x^2-x+2y

Therefore:


\begin{aligned}\sf Perimeter & = 2(\sf width + length)\\& = 2 \left((x+4y)+(4x^2-x+2y)\right)\\& = 2(x+4y+4x^2-x+2y)\\& = 2x+8y+8x^2-2x+4y\\& = 8x^2+2x-2x+8y+4y\\& = 8x^2+12y\end{aligned}

User Prl
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2.8k points
20 votes
20 votes

Answer:

  • P = 8x² + 12y units

Explanation:

Given sides of rectangle:

  • x + 4y
  • 4x² - x + 2y

Its perimeter is:

  • P = 2(l + w)
  • P = 2(x + 4y + 4x² - x + 2y)
  • P = 2(4x² + 6y)
  • P = 8x² + 12y
User PhDeOliveira
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2.8k points