Question

Question 26 (1 point)

Find the distance between points P(7.1) and Q(5,7) to the nearest tenth.
PQ =

Answer 1

PQ=1.4 I think

Explanation:

Answer 2

The answer is 6.3 units

Explanation:

The distance between two points can be found by using the formula

`d = \sqrt{ ({x1 - x2})^(2) + ({y1 - y2})^(2) } \\`

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

P(7,,1) and Q(5,7)

We have

`|PQ| = \sqrt{ ({7 - 5})^(2) + ({1 - 7})^(2) } \\ = \sqrt{ {2}^(2) + ({ - 6})^(2) } \\ = √(4 + 36 ) \: \: \: \: \: \: \: \: \: \\ = √(40) \: \: \\ = 2 √(10) \\ = 6.32455532...`

We have the final answer as

6.3 units to the nearest tenth

Hope this helps you