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What is the equation of a line that is parallel to the line y = 5x – 1 and passes

through the point (4, -3)?
A. y = 5x + 19
B. y = -5x + 17
C. y = 5x – 23
D.y= -1/5x - 11/5

User FRIDDAY
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1 Answer

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Final answer:

The equation of the line that is parallel to y = 5x - 1 and passes through the point (4, -3) is y = 5x - 23.

Step-by-step explanation:

To find the equation of a line that is parallel to the line y = 5x - 1 and passes through the point (4, -3), we can use the fact that parallel lines have the same slope. The given line has a slope of 5, so the parallel line will also have a slope of 5. We can use the point-slope form of a linear equation to find the equation of the parallel line. The equation is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope. Plugging in the values, we get y - (-3) = 5(x - 4), which simplifies to y + 3 = 5x - 20. Rearranging the equation, we get y = 5x - 23. Therefore, the equation of the line that is parallel to y = 5x - 1 and passes through the point (4, -3) is y = 5x - 23.

User Doannx
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