Question

The temperature dropped from 90° at noon to 50° by midnight. What is the percent decrease in temperature

Round your answer to the nearest whole percent and include your percent sign,

Answer 1

• Initial temperature=t_i=90°C
• Final temperature=t_f=50°C

Total change in temperature

• ∆T=90-50=40°C

Percentage:-

`\\ \sf\longmapsto (\Delta T)/(t_i)* 100`

`\\ \sf\longmapsto (40)/(90)* 100`

`\\ \sf\longmapsto (400)/(9)`

`\\ \sf\longmapsto 44.4\%`

Answer 2

Percent decrease
= [(90-50) / 90 ] x 100%
= (40 / 90) x 100%
= 44.4%
= 44%