Given :
A sailor is 30 m above the water in the crow's nest on a sailboat.
The sailor encounters an orca surface at an angle of depression of 15 degrees.
The crows nest is 20 m horizontally from the bow (front) of the boat.
To Find :
How far in front of the boat is the orca.
Solution :
Let, distance of boat front from the crow's nest is x.
So,
![(30)/(20+x)=tan \ 15^(\circ)\\\\x=(30)/(tan \ 15^(\circ))-20\\\\x=111.94-20\\\\x=91.94\ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/9ol9sxaar3ew4hxyvgexumahjzumbme25j.png)
Hence, this is the required solution.