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(x-3)^2+(y+4)^2=36 geometry

1 Answer

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Answer:

Simplifying

(x + -2) * 2 + (y + -4) * 2 = 36

Reorder the terms:

(-2 + x) * 2 + (y + -4) * 2 = 36

Reorder the terms for easier multiplication:

2(-2 + x) + (y + -4) * 2 = 36

(-2 * 2 + x * 2) + (y + -4) * 2 = 36

(-4 + 2x) + (y + -4) * 2 = 36

Reorder the terms:

-4 + 2x + (-4 + y) * 2 = 36

Reorder the terms for easier multiplication:

-4 + 2x + 2(-4 + y) = 36

-4 + 2x + (-4 * 2 + y * 2) = 36

-4 + 2x + (-8 + 2y) = 36

Reorder the terms:

-4 + -8 + 2x + 2y = 36

Combine like terms: -4 + -8 = -12

-12 + 2x + 2y = 36

Solving

-12 + 2x + 2y = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 2x + 12 + 2y = 36 + 12

Reorder the terms:

-12 + 12 + 2x + 2y = 36 + 12

Combine like terms: -12 + 12 = 0

0 + 2x + 2y = 36 + 12

2x + 2y = 36 + 12

Combine like terms: 36 + 12 = 48

2x + 2y = 48

Add '-2y' to each side of the equation.

2x + 2y + -2y = 48 + -2y

Combine like terms: 2y + -2y = 0

2x + 0 = 48 + -2y

2x = 48 + -2y

Divide each side by '2'.

x = 24 + -1y

Simplifying

x = 24 + -1y

Explanation:

User Sergio Belevskij
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