Question

Please help!!

Explain the difference between using the cosine ratio to solve for a missing angle in a right
triangle versus using the secant ratio. You must use complete sentences and any evidence
needed (such as an example) to prove your point of view.

Answer 1

Explanation:

Suppose a right triangle ABC in which

BC=3 units and AC=5 unit and angle B=90 degree

Let x be the missing angle of right triangle

We know that

Hence, there is no difference between using cosine ratio to solve for a missing angle in a right triangle versus using the secant ratio.

Answer 2

In trigonometry, secant in a right triangle, is the reciprocal of the cosine of an angle symbol: sec while cosine is in a right triangle, is the ratio of the length of the side adjacent to an acute angle to the length of the hypotenuse.

The cosine of an angle is the ratio of the length of the side adjacent to the angle divided by the length of the hypotenuse of the triangle. The cosine of ∠A will be abbreviated as cos ∠A

The secant of x is 1 divided by the cosine of x: sec x = 1 cos x , and the cosecant of x is defined to be 1 divided by the sine of x: csc x = 1 sin x .