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1. Angle MJP

2. Angle JKL
3. Angle NKP
4. Angle KLJ
5. Side NP
6. Side KM
7. Side KP
8. Side PL

1. Angle MJP 2. Angle JKL 3. Angle NKP 4. Angle KLJ 5. Side NP 6. Side KM 7. Side-example-1
User Chuysbz
by
4.6k points

1 Answer

5 votes

Answer:

See explanation

Explanation:

For triangle JNL: JLN = 180 - (90 + 39) = 51

so JLP = 51 - 28 = 23

8. side PL: cos JLP = OL/PL

=> PL = OL/cos JLP = 24/cos23 = 24/0.92 = 26

5. Side NP

sin NLP = NP/PL => NP = PL(sin NLP) = 26(sin28) = 26(0.47) = 12.22

7. side KP:

KP^2 = NP^2 + 30^2 = 12.22^2 + 30^2 = 149.33 + 900 = 1049.33

KP = 32.39

6. Side KM: KP^2 = KM^2 + 13^2

KM^2 = KP^2 - 13^2 = 1049.33 - 169 = 880.33

KM = 29.67

4. Angle KLJ: equals to angle NLJ

NLJ = 180 - (90 + 39) = 51

3. Angle NKP: cosNKP = 30/KP = 30/32.39 = 0.926

=> NKP = 22 degrees

2. Angle JKL

sin MKP = 13/KP = 13/32.39 = 0.401

=> MKP = 24 degrees

JKL = MKP + NKP = 24 + 22 = 46 degrees

1. Angle MJP

MJP + 39 = 180 - (JKL + KLJ)

MJP = 180 - (46 + 51) - 39 = 44

Let me know if I miss anything

User Gopalakrishnan
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5.2k points