Question

PLEASE HELP
find value of x and y

Answer 1

Given :

• There is a quadrilateral.
• Two sides of the quadrilateral are parallel .
• Four angles are 96° , 2x° , 94° & ( 3y + 44 )°.

To Find :-

• The value of x & y .

Solution :-

Here , 96° & 2x° are co - interior angles and we know that the sum of co - Interior angles is 180°.

⇒ 96° + 2x = 180° .

⇒ 2x = 180° - 96° .

⇒ 2x = 84° .

⇒ x =
`\red{\sf (84^(\circ))/(2)}`

`\bf\longmapsto x = 42^(\circ)`

Hence value of x is 42° .

Similarly , 94° & ( 3y + 44) ° are co- interior angles

⇒ 94° + ( 3y + 44)° = 180° .

⇒ ( 3y + 44 )° = 180° - 94° .

⇒ 3y + 44° = 86°.

⇒ 3y = 86° - 44° .

⇒ 3y = 42° .

⇒ y =
`\sf \red{(42^(\circ))/(3)}`

`\bf\longmapsto y = 14^(\circ)`

Hence the value of y is 14°.