Question

3. A wye-connected load has a voltage of 480 V applied to it. What is the voltage dropped across each phase?

Answer 1

`E_s = 277.13V`

Step-by-step explanation:

Given

`Load\ Voltage = 480V`

Required

Determine the voltage dropped in each stage.

The relation between the load voltage and the voltage dropped in each stage is

`E_l = E_s * \sqrt3`

Where

`E_l = 480`

So, we have:

`480 = E_s * \sqrt3`

Solve for
`E_s`

`E_s = (480)/(\sqrt3)`

`E_s = (480)/(1.73205080757)`

`E_s = 277.128129211`

`E_s = 277.13V`

Hence;

The voltage dropped at each phase is approximately 277.13V