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Rewrite by completing the square 2x^2+7x+6=0
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Rewrite by completing the square 2x^2+7x+6=0

User Danilo Valente
by
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2 Answers

3 votes

Answer:


2x^2+7x+6=0\\\\2(x^2+\frac72x+3)=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2-(\frac74)^2+3]=0\\\\2[x^2+2\cdot x\cdot\frac74+(\frac74)^2]-2(\frac74)^2+6=0 \\\\2(x+\frac74)^2-2\cdot(49)/(16)+6=0\\\\2(x+\frac74)^2-\frac{49}8+\frac{48}8=0\\\\2(x+\frac74)^2-\frac18=0

User Robert Campbell
by
5.9k points
5 votes

Answer:

(x+7/4)^2=1/16

Explanation:

User Liuliu
by
5.9k points
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