Question

5 to the power of minus 1, 0.5, minus 5, 5 power of 0 from smallest to biggest

Answer 1

`\huge\boxed{-5,\ 5^(-1),\ 0.5,\ 5^0}`

Explanation:

`5^(-1)\qquad\text{use}\ a^(-n)=(1)/(a^n)\ \text{for}\ a\\eq0\\\\5^(-1)=(1)/(5^1)=(1)/(5)=(1\cdot2)/(5\cdot2)=(2)/(10)=0.2\\\\===============\\0.5\\\\===============\\-5\\\\===============\\5^0=1\ \text{because}\ a^0=1\ \text{for any number}`

`-5<0.2<0.5<1\\\\\text{therefore}\\\\-5<5^(-1)<0.5<5^0`

Answer 2

-5, 5^-1, 0.5, 5^0

Explanation:

The smallest number here is -5 as it is the only negative number.

5^-1 is equivalent to 1/(5^1) = 1/5, or 0.2,

5^0 = 1 as anything to the power of 0 is 1.

0.2 is larger than -5 but smaller than 0.5 and 1 and is therefore the second smallest.

0.5 is smaller than 1 and is therefore second largest.

So the final order is:

-5, 5^-1 (=0.2), 0.5, 5^0 (=1)

Hope this helped!